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{{Short description|Thermodynamic process in which no mass or heat is exchanged with surroundings}}
{{Short description|Thermodynamic process in which no mass or heat is exchanged with surroundings}}
{{About|adiabatic processes in thermodynamics|the adiabatic theorem in quantum mechanics|adiabatic theorem}}
{{About|adiabatic processes in thermodynamics|the adiabatic theorem in quantum mechanics|Adiabatic theorem}}
{{Thermodynamics|cTopic=[[Thermodynamic system|Systems]]}}
{{Thermodynamics|cTopic=systems}}


An '''adiabatic process''' (''adiabatic'' {{etymology|grc|''{{Wikt-lang|grc|ἀδιάβατος}}'' ({{grc-transl|ἀδιάβατος}})|impassable}}) is a type of [[thermodynamic process]] that occurs without transferring [[heat]] between the [[thermodynamic system]] and its [[Environment (systems)|environment]]. Unlike an [[isothermal process]], an adiabatic process transfers energy to the surroundings only as [[Work (thermodynamics)|work]] and/or mass flow.<ref name="Carathéodory">{{cite journal |last=Carathéodory |first=C. |author-link=Constantin Carathéodory |date=1909 |title=Untersuchungen über die Grundlagen der Thermodynamik |url=https://zenodo.org/record/1428268 |journal=Mathematische Annalen |volume=67 |issue=3 |pages=355–386 |doi=10.1007/BF01450409 |s2cid=118230148}}. A translation may be found [http://neo-classical-physics.info/uploads/3/0/6/5/3065888/caratheodory_-_thermodynamics.pdf here] {{Webarchive|url=https://web.archive.org/web/20191012152205/http://neo-classical-physics.info/uploads/3/0/6/5/3065888/caratheodory_-_thermodynamics.pdf|date=2019-10-12}}. Also a mostly reliable [https://books.google.com/books?id=xwBRAAAAMAAJ&q=Investigation+into+the+foundations translation is to be found] in {{cite book |last=Kestin |first=J. |title=The Second Law of Thermodynamics |date=1976 |publisher=Dowden, Hutchinson & Ross |location=Stroudsburg, Pennsylvania |language=en-us}}</ref><ref name="Bailyn 21">{{cite book |last=Bailyn |first=M. |title=A Survey of Thermodynamics |date=1994 |publisher=American Institute of Physics Press |isbn=0-88318-797-3 |location=New York, New York |page=21 |language=en-us}}</ref> As a key concept in [[thermodynamics]], the adiabatic process supports the theory that explains the [[first law of thermodynamics]]. The opposite term to "adiabatic" is ''diabatic''.
An '''adiabatic process''' (''adiabatic'' {{etymology|grc|''{{Wikt-lang|grc|ἀδιάβατος}}'' ({{grc-transl|ἀδιάβατος}})|impassable}}) is a type of [[thermodynamic process]] whereby a transfer of [[energy]] between the [[thermodynamic system]] and its [[Environment (systems)|environment]] is accompanied neither by a transfer of [[entropy]] nor of amounts of constituents. Unlike an [[isothermal process]], an adiabatic process transfers energy to the surroundings only as [[work (thermodynamics)|work]] and/or mass flow.<ref name=Carathéodory>{{cite journal |last=Carathéodory |first=C. |author-link=Constantin Carathéodory |date=1909 |title=Untersuchungen über die Grundlagen der Thermodynamik |lang=de |trans-title=Investigation into the foundations of thermodynamics |journal=[[Mathematische Annalen]] |volume=67 |issue=3 |pages=355–386 |doi=10.1007/BF01450409 |s2cid=118230148 |url=https://zenodo.org/record/1428268 }} <br/>{{cite web |title=A translation may be found here |website=neo-classical-physics.info |url=http://neo-classical-physics.info/uploads/3/0/6/5/3065888/caratheodory_-_thermodynamics.pdf |archive-url=https://web.archive.org/web/20191012152205/http://neo-classical-physics.info/uploads/3/0/6/5/3065888/caratheodory_-_thermodynamics.pdf |archive-date=2019-10-12}} <br/>Also, a mostly reliable translation is to be found in {{cite book |last=Kestin |first=J. |year=1976 |section=Investigation into the foundations ... |title=The Second Law of Thermodynamics |publisher=Dowden, Hutchinson & Ross |location=Stroudsburg, Pennsylvania |lang=en-us |section-url=https://books.google.com/books?id=xwBRAAAAMAAJ&q=Investigation+into+the+foundations }}</ref><ref name=Bailyn>{{cite book |last=Bailyn |first=M. |year=1994 |title=A Survey of Thermodynamics |publisher=American Institute of Physics Press |isbn=0-88318-797-3 |location=New York, NY |page=21 |lang=en-us }} </ref>{{rp|style=ama|p=21}}<ref>{{cite journal |last1=Zanchini |first1=E. |last2=Beretta |first2=G.P. |year=2014 |title=Recent progress in the definition of thermodynamic entropy |journal=[[Entropy (journal)|Entropy]] |volume=16 |issue=3 |pages=1547–1570 |doi=10.3390/e16031547 |doi-access=free |arxiv=1403.5772 |bibcode=2014Entrp..16.1547Z }}</ref> As a key concept in [[thermodynamics]], the adiabatic process supports the theory that explains the [[first law of thermodynamics]]. The opposite term to "adiabatic" is ''diabatic''.


Some chemical and physical processes occur too rapidly for energy to enter or leave the system as heat, allowing a convenient "adiabatic approximation".<ref name="Bailyn 53">Bailyn, M. (1994), pp. 52–53.</ref> For example, the [[adiabatic flame temperature]] uses this approximation to calculate the upper limit of [[fire|flame]] temperature by assuming combustion loses no heat to its surroundings.
Some chemical and physical processes occur too rapidly for energy to enter or leave the system as heat, allowing a convenient "adiabatic approximation".<ref name=Bailyn/>{{rp|style=ama|pp=52–53}} For example, the [[adiabatic flame temperature]] uses this approximation to calculate the upper limit of [[fire|flame]] temperature by assuming combustion loses no heat to its surroundings.


In [[meteorology]], adiabatic expansion and cooling of moist air, which can be triggered by winds flowing up and over a mountain for example, can cause the [[water vapor]] pressure to exceed the [[Vapor pressure|saturation vapor pressure]]. Expansion and cooling beyond the saturation vapor pressure is often idealized as a ''pseudo-adiabatic process'' whereby excess vapor instantly [[precipitation|precipitates]] into water droplets. The change in temperature of air undergoing pseudo-adiabatic expansion differs from air undergoing adiabatic expansion because [[latent heat]] is released by precipitation.<ref>{{cite web|url=http://glossary.ametsoc.org/wiki/Pseudoadiabatic_process|title=pseudoadiabatic process|publisher=[[American Meteorological Society]]|access-date=November 3, 2018}}</ref>
In [[meteorology]], adiabatic expansion and cooling of moist air, which can be triggered by winds flowing up and over a mountain for example, can cause the [[water vapor]] pressure to exceed the [[Vapor pressure|saturation vapor pressure]]. Expansion and cooling beyond the saturation vapor pressure is often idealized as a ''pseudo-adiabatic process'' whereby excess vapor instantly [[precipitation|precipitates]] into water droplets. The change in temperature of air undergoing pseudo-adiabatic expansion differs from air undergoing adiabatic expansion because [[latent heat]] is released by precipitation.<ref>{{cite web|url=http://glossary.ametsoc.org/wiki/Pseudoadiabatic_process|title=pseudoadiabatic process|publisher=[[American Meteorological Society]]|access-date=November 3, 2018}}</ref>
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==Description==
==Description==


A process without transfer of heat to or from a system, so that {{math|1=''Q'' = 0}}, is called adiabatic, and such a system is said to be adiabatically isolated.<ref>{{cite book |last=Tisza |first=L. |title=Generalized Thermodynamics |date=1966 |publisher=MIT Press |location=Cambridge, Massachusetts |page=48 |language=en-us |quote=(adiabatic partitions inhibit the transfer of heat and mass) |author-link=László Tisza}}</ref><ref>Münster, A. (1970), p. 48: "mass is an adiabatically inhibited variable."</ref> The simplifying assumption frequently made is that a process is adiabatic. For example, the compression of a gas within a cylinder of an engine is assumed to occur so rapidly that on the time scale of the compression process, little of the system's energy can be transferred out as heat to the surroundings. Even though the cylinders are not insulated and are quite conductive, that process is idealized to be adiabatic. The same can be said to be true for the expansion process of such a system.
A process without transfer of [[thermal energy]] (heat) to or from a system, so that {{math|1=''Q'' = 0}}, is called adiabatic, and such a system is said to be adiabatically isolated.<ref>{{cite book |last=Tisza |first=L. |title=Generalized Thermodynamics |date=1966 |publisher=MIT Press |location=Cambridge, Massachusetts |page=48 |language=en-us |quote=(adiabatic partitions inhibit the transfer of heat and mass) |author-link=László Tisza}}</ref><ref>Münster, A. (1970), p. 48: "mass is an adiabatically inhibited variable."</ref> The simplifying assumption frequently made is that a process is adiabatic. For example, the compression of a gas within a cylinder of an engine is assumed to occur so rapidly that on the time scale of the compression process, little of the system's energy can be transferred out as heat to the surroundings. Even though the cylinders are not insulated and are quite conductive, that process is idealized to be adiabatic. The same can be said to be true for the expansion process of such a system.


The assumption of adiabatic isolation is useful and often combined with other such idealizations to calculate a good first approximation of a system's behaviour. For example, according to [[Pierre-Simon Laplace|Laplace]], when sound travels in a gas, there is no time for heat conduction in the medium, and so the propagation of sound is adiabatic. For such an adiabatic process, the [[Elastic modulus|modulus of elasticity]] ([[Young's modulus]]) can be expressed as {{math|1=''E'' = ''γP''}}, where {{math|''γ''}} is the [[Heat capacity ratio|ratio of specific heats]] at constant pressure and at [[constant volume]] ({{math|1=''γ'' = {{sfrac|''C<sub>p</sub>''|''C<sub>v</sub>''}}}}) and {{math|''P''}} is the pressure of the gas.
The assumption of adiabatic isolation is useful and often combined with other such idealizations to calculate a good first approximation of a system's behaviour. For example, according to [[Pierre-Simon Laplace|Laplace]], when sound travels in a gas, there is no time for heat conduction in the medium, and so the propagation of sound is adiabatic. For such an adiabatic process, the [[Elastic modulus|modulus of elasticity]] ([[Young's modulus]]) can be expressed as {{math| ''E'' {{=}} ''γP''}}, where {{mvar|γ}} is the [[Heat capacity ratio|ratio of specific heats]] at constant pressure and at [[constant volume]] ({{math| ''γ'' {{=}} {{sfrac|''C<sub>p</sub>''|''C<sub>v</sub>''}}}}) and {{math|''P''}} is the pressure of the gas.


=== Various applications of the adiabatic assumption ===
===Various applications of the adiabatic assumption===


For a closed system, one may write the [[first law of thermodynamics]] as {{math|1=Δ''U'' = ''Q'' − ''W''}}, where {{math|Δ''U''}} denotes the change of the system's internal energy, {{math|''Q''}} the quantity of energy added to it as heat, and {{math|''W''}} the work done by the system on its surroundings.
For a closed system, one may write the [[first law of thermodynamics]] as {{math|Δ''U'' {{=}} ''Q'' − ''W''}}, where {{math|Δ''U''}} denotes the change of the system's internal energy, {{mvar|Q}} the quantity of energy added to it as heat, and {{mvar|W}} the work done by the system on its surroundings.


*If the system has such rigid walls that work cannot be transferred in or out ({{math|1=''W'' = 0}}), and the walls are not adiabatic and energy is added in the form of heat ({{math|''Q'' > 0}}), and there is no phase change, then the temperature of the system will rise.
* If the system has such rigid walls that work cannot be transferred in or out ({{math|''W'' {{=}} 0}}), and the walls are not adiabatic and energy is added in the form of heat ({{math|''Q'' > 0}}), and there is no phase change, then the temperature of the system will rise.
*If the system has such rigid walls that pressure–volume work cannot be done, but the walls are adiabatic ({{math|1=''Q'' = 0}}), and energy is added as [[Isochoric process|isochoric]] (constant volume) work in the form of friction or the stirring of a [[viscous]] fluid within the system ({{math|''W'' < 0}}), and there is no phase change, then the temperature of the system will rise.
* If the system has such rigid walls that pressure–volume work cannot be done, but the walls are adiabatic ({{math|''Q'' {{=}} 0}}), and energy is added as [[Isochoric process|isochoric]] (constant volume) work in the form of friction or the stirring of a [[viscous]] fluid within the system ({{math|''W'' < 0}}), and there is no phase change, then the temperature of the system will rise.
*If the system walls are adiabatic ({{math|1=''Q'' = 0}}) but not rigid ({{math|''W'' ≠ 0}}), and, in a fictive idealized process, energy is added to the system in the form of frictionless, non-viscous pressure–volume work ({{math|''W'' < 0}}), and there is no phase change, then the temperature of the system will rise. Such a process is called an [[isentropic process]] and is said to be "reversible". Ideally, if the process were reversed the energy could be recovered entirely as work done by the system. If the system contains a compressible gas and is reduced in volume, the uncertainty of the position of the gas is reduced, and seemingly would reduce the entropy of the system, but the temperature of the system will rise as the process is isentropic ({{math|1=Δ''S'' = 0}}). Should the work be added in such a way that friction or viscous forces are operating within the system, then the process is not isentropic, and if there is no phase change, then the temperature of the system will rise, the process is said to be "irreversible", and the work added to the system is not entirely recoverable in the form of work.
* If the system walls are adiabatic ({{math|''Q'' {{=}} 0}}) but not rigid ({{math|''W'' ≠ 0}}), and, in a fictive idealized process, energy is added to the system in the form of frictionless, non-viscous pressure–volume work ({{math|''W'' < 0}}), and there is no phase change, then the temperature of the system will rise. Such a process is called an [[isentropic process]] and is said to be "reversible". Ideally, if the process were reversed the energy could be recovered entirely as work done by the system. If the system contains a compressible gas and is reduced in volume, the uncertainty of the position of the gas is reduced, and seemingly would reduce the entropy of the system, but the temperature of the system will rise as the process is isentropic ({{math|Δ''S'' {{=}} 0}}). Should the work be added in such a way that friction or viscous forces are operating within the system, then the process is not isentropic, and if there is no phase change, then the temperature of the system will rise, the process is said to be "irreversible", and the work added to the system is not entirely recoverable in the form of work.
*If the walls of a system are not adiabatic, and energy is transferred in as heat, entropy is transferred into the system with the heat. Such a process is neither adiabatic nor isentropic, having {{math|''Q'' > 0}}, and {{math|Δ''S'' > 0}} according to the [[second law of thermodynamics]].
* If the walls of a system are not adiabatic, and energy is transferred in as heat, entropy is transferred into the system with the heat. Such a process is neither adiabatic nor isentropic, having {{math|''Q'' > 0}}, and {{math|Δ''S'' > 0}} according to the [[second law of thermodynamics]].


Naturally occurring adiabatic processes are irreversible (entropy is produced).
Naturally occurring adiabatic processes are irreversible (entropy is produced).
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The adiabatic compression of a gas causes a rise in temperature of the gas. Adiabatic expansion against pressure, or a spring, causes a drop in temperature. In contrast, [[free expansion]] is an [[isothermal]] process for an ideal gas.
The adiabatic compression of a gas causes a rise in temperature of the gas. Adiabatic expansion against pressure, or a spring, causes a drop in temperature. In contrast, [[free expansion]] is an [[isothermal]] process for an ideal gas.


'''Adiabatic compression''' occurs when the pressure of a gas is increased by work done on it by its surroundings, e.g., a [[piston]] compressing a gas contained within a cylinder and raising the temperature where in many practical situations heat conduction through walls can be slow compared with the compression time. This finds practical application in [[diesel engines]] which rely on the lack of heat dissipation during the compression stroke to elevate the fuel vapor temperature sufficiently to ignite it.
===Adiabatic compression===
Adiabatic compression occurs when the pressure of a gas is increased by work done on it by its surroundings, e.g., a [[piston]] compressing a gas contained within a cylinder and raising the temperature where in many practical situations heat conduction through walls can be slow compared with the compression time. This finds practical application in [[diesel engines]] which rely on the lack of heat dissipation during the compression stroke to elevate the fuel vapor temperature sufficiently to ignite it.


Adiabatic compression occurs in the [[Earth's atmosphere]] when an [[air mass]] descends, for example, in a [[Katabatic wind]], [[Foehn wind]], or [[Chinook wind]] flowing downhill over a mountain range. When a parcel of air descends, the pressure on the parcel increases. Because of this increase in pressure, the parcel's volume decreases and its temperature increases as work is done on the parcel of air, thus increasing its internal energy, which manifests itself by a rise in the temperature of that mass of air. The parcel of air can only slowly dissipate the energy by conduction or radiation (heat), and to a first approximation it can be considered adiabatically isolated and the process an adiabatic process.
Adiabatic compression occurs in the [[Earth's atmosphere]] when an [[air mass]] descends, for example, in a [[Katabatic wind]], [[Foehn wind]], or [[Chinook wind]] flowing downhill over a mountain range. When a parcel of air descends, the pressure on the parcel increases. Because of this increase in pressure, the parcel's volume decreases and its temperature increases as work is done on the parcel of air, thus increasing its internal energy, which manifests itself by a rise in the temperature of that mass of air. The parcel of air can only slowly dissipate the energy by conduction or radiation (heat), and to a first approximation it can be considered adiabatically isolated and the process an adiabatic process.


'''Adiabatic expansion''' occurs when the pressure on an adiabatically isolated system is decreased, allowing it to expand in size, thus causing it to do work on its surroundings. When the pressure applied on a parcel of gas is reduced, the gas in the parcel is allowed to expand; as the volume increases, the temperature falls as its internal energy decreases. Adiabatic expansion occurs in the Earth's atmosphere with [[orographic lifting]] and [[lee waves]], and this can form [[Pileus (meteorology)|pilei]] or [[lenticular cloud]]s.
===Adiabatic expansion===
Adiabatic expansion occurs when the pressure on an adiabatically isolated system is decreased, allowing it to expand in size, thus causing it to do work on its surroundings. When the pressure applied on a parcel of gas is reduced, the gas in the parcel is allowed to expand; as the volume increases, the temperature falls as its internal energy decreases. Adiabatic expansion occurs in the Earth's atmosphere with [[orographic lifting]] and [[lee waves]], and this can form [[Pileus (meteorology)|pilei]] or [[lenticular cloud]]s.


Due in part to adiabatic expansion in mountainous areas, snowfall infrequently occurs in some parts of the [[Sahara desert]].<ref>{{cite web |last1=Knight |first1=Jasper |title=Snowfall in the Sahara desert: an unusual weather phenomenon |url=https://theconversation.com/snowfall-in-the-sahara-desert-an-unusual-weather-phenomenon-176037 |website=The Conversation |access-date=3 March 2022 |date=31 January 2022}}</ref>
Due in part to adiabatic expansion in mountainous areas, snowfall actually occurs in some parts of the [[Sahara desert]].<ref>{{cite web |last1=Knight |first1=Jasper |title=Snowfall in the Sahara desert: an unusual weather phenomenon |url=https://theconversation.com/snowfall-in-the-sahara-desert-an-unusual-weather-phenomenon-176037 |website=The Conversation |access-date=3 March 2022 |date=31 January 2022}}</ref>


Adiabatic expansion does not have to involve a fluid. One technique used to reach very low temperatures (thousandths and even millionths of a degree above absolute zero) is via [[adiabatic demagnetization|adiabatic demagnetisation]], where the change in [[magnetic field]] on a magnetic material is used to provide adiabatic expansion. Also, the contents of an [[expanding universe]] can be described (to first order) as an adiabatically expanding fluid. (See [[heat death of the universe]].)
Adiabatic expansion does not have to involve a fluid. One technique used to reach very low temperatures (thousandths and even millionths of a degree above absolute zero) is via [[adiabatic demagnetization|adiabatic demagnetisation]], where the change in [[magnetic field]] on a magnetic material is used to provide adiabatic expansion. Also, the contents of an [[expanding universe]] can be described (to first order) as an adiabatically expanding fluid. (See [[heat death of the universe]].)
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Rising magma also undergoes adiabatic expansion before eruption, particularly significant in the case of magmas that rise quickly from great depths such as [[kimberlite]]s.<ref name="Kavanagh">{{cite journal|last1=Kavanagh|first1=J. L.|last2=Sparks |first2=R. S. J.|year=2009|title=Temperature changes in ascending kimberlite magmas|journal=Earth and Planetary Science Letters|publisher=[[Elsevier]]|volume=286|issue=3–4|pages=404–413|doi=10.1016/j.epsl.2009.07.011|url=https://monash.academia.edu/JanineKavanagh/Papers/114092/Temperature_changes_in_ascending_kimberlite_magma|access-date=18 February 2012|bibcode = 2009E&PSL.286..404K }}</ref>
Rising magma also undergoes adiabatic expansion before eruption, particularly significant in the case of magmas that rise quickly from great depths such as [[kimberlite]]s.<ref name="Kavanagh">{{cite journal|last1=Kavanagh|first1=J. L.|last2=Sparks |first2=R. S. J.|year=2009|title=Temperature changes in ascending kimberlite magmas|journal=Earth and Planetary Science Letters|publisher=[[Elsevier]]|volume=286|issue=3–4|pages=404–413|doi=10.1016/j.epsl.2009.07.011|url=https://monash.academia.edu/JanineKavanagh/Papers/114092/Temperature_changes_in_ascending_kimberlite_magma|access-date=18 February 2012|bibcode = 2009E&PSL.286..404K }}</ref>


In the Earth's convecting mantle (the asthenosphere) beneath the [[lithosphere]], the mantle temperature is approximately an adiabat. The slight decrease in temperature with shallowing depth is due to the decrease in pressure the shallower the material is in the Earth.<ref>{{Cite book|title=Geodynamics|url=https://archive.org/details/geodynamics00dltu|url-access=limited|last=Turcotte and Schubert|publisher=Cambridge University Press|year=2002|isbn=0-521-66624-4|location=Cambridge|pages=[https://archive.org/details/geodynamics00dltu/page/n199 185]}}</ref>
In the Earth's convecting [[Earth's mantle|mantle]] (the asthenosphere) beneath the [[lithosphere]], the mantle temperature is approximately an adiabat. The slight decrease in temperature with shallowing depth is due to the decrease in pressure the shallower the material is in the Earth.<ref>{{Cite book|title=Geodynamics|url=https://archive.org/details/geodynamics00dltu|url-access=limited|last=Turcotte and Schubert|publisher=Cambridge University Press|year=2002|isbn=0-521-66624-4|location=Cambridge|pages=[https://archive.org/details/geodynamics00dltu/page/n199 185]}}</ref>


Such temperature changes can be quantified using the [[ideal gas law]], or the [[hydrostatic equation]] for atmospheric processes.
Such temperature changes can be quantified using the [[ideal gas law]], or the [[hydrostatic equation]] for atmospheric processes.
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[[Image:Adiabatic.svg|thumb|upright=1.2|For a simple substance, during an adiabatic process in which the volume increases, the [[internal energy]] of the working substance must decrease.]]
[[Image:Adiabatic.svg|thumb|upright=1.2|For a simple substance, during an adiabatic process in which the volume increases, the [[internal energy]] of the working substance must decrease.]]
The mathematical equation for an [[ideal gas]] undergoing a reversible (i.e., no entropy generation) adiabatic process can be represented by the [[polytropic process]] equation<ref name="Bailyn 53"/>
The mathematical equation for an [[ideal gas]] undergoing a reversible (i.e., no entropy generation) adiabatic process can be represented by the [[polytropic process]] equation<ref name=Bailyn/>{{rp|style=ama|p=53}}


<math display="block"> P V^\gamma = \text{constant}, </math>
<math display="block"> P\ V^\gamma = \mathsf{constant}\ ,</math>


where {{math|''P''}} is pressure, {{math|''V''}} is volume, and {{math|''γ''}} is the [[adiabatic index]] or heat capacity ratio defined as
where {{mvar|P}} is pressure, {{mvar|V}} is volume, and {{mvar|γ}} is the [[adiabatic index]] or heat capacity ratio defined as


<math display="block"> \gamma = \frac{C_P}{C_V} = \frac{f + 2}{f}. </math>
<math display="block"> \gamma = \frac{C_P}{C_V} = \frac{f + 2}{f} ~.</math>


Here {{math|''C<sub>P</sub>''}} is the [[specific heat]] for constant pressure, {{math|''C<sub>V</sub>''}} is the specific heat for constant volume, and {{math|''f''}} is the number of [[Degrees of freedom (physics and chemistry)|degrees of freedom]] (3 for a monatomic gas, 5 for a diatomic gas or a gas of linear molecules such as carbon dioxide).
Here {{mvar| C{{sub|P}} }} is the [[specific heat]] for constant pressure, {{mvar| C{{sub|V}} }} is the specific heat for constant volume, and {{mvar|f}} is the number of [[Degrees of freedom (physics and chemistry)|degrees of freedom]] (3 for a monatomic gas, 5 for a diatomic gas or a gas of linear molecules such as carbon dioxide).


For a monatomic ideal gas, {{math|1=''γ'' = {{sfrac|5|3}}}}, and for a diatomic gas (such as [[nitrogen]] and [[oxygen]], the main components of air), {{math|1=''γ'' = {{sfrac|7|5}}}}.<ref>{{cite web |url=http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/adiab.html |title=Adiabatic Process |website=HyperPhysics |publisher=Georgia State University}}</ref> Note that the above formula is only applicable to classical ideal gases (that is, gases far above absolute zero temperature) and not [[Bose–Einstein condensate|Bose–Einstein]] or [[Fermionic condensate|Fermi gases]].
For a monatomic ideal gas, {{nobr|{{math|''γ'' {{=}} {{sfrac|5|3}}}},}} and for a diatomic gas (such as [[nitrogen]] and [[oxygen]], the main components of air), {{nobr|{{math|''γ'' {{=}} {{sfrac|7|5}}}}.}}<ref>{{cite web |url=http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/adiab.html |title=Adiabatic Process |website=HyperPhysics |publisher=Georgia State University}}</ref> Note that the above formula is only applicable to classical ideal gases (that is, gases far above absolute zero temperature) and not [[Bose–Einstein condensate|Bose–Einstein]] or [[Fermionic condensate|Fermi gases]].


One can also use the ideal gas law to rewrite the above relationship between {{math|''P''}} and {{math|''V''}} as <ref name="Bailyn 53"/>
One can also use the ideal gas law to rewrite the above relationship between {{mvar|P}} and {{mvar|V}} as<ref name=Bailyn/>{{rp|style=ama|p=53}}


<math display="block">\begin{align}
<math display="block">\begin{align}
P^{1-\gamma} T^\gamma &= \text{constant},\\
P^{1-\gamma}\ T^\gamma &= \mathsf{constant}\ ,\\
TV^{\gamma - 1} &= \text{constant}
T\ V^{\gamma - 1} &= \mathsf{constant} ~.
\end{align}</math>
\end{align}</math>


where ''T'' is the absolute or [[thermodynamic temperature]].
where {{mvar|T}} is the absolute or [[thermodynamic temperature]].


===Example of adiabatic compression===
===Example of adiabatic compression===
The compression stroke in a [[gasoline engine]] can be used as an example of adiabatic compression. The model assumptions are: the uncompressed volume of the cylinder is one litre (1&nbsp;L = 1000&nbsp;cm<sup>3</sup> = 0.001&nbsp;m<sup>3</sup>); the gas within is the air consisting of molecular nitrogen and oxygen only (thus a diatomic gas with 5 degrees of freedom, and so {{math|1=''γ'' = {{sfrac|7|5}}}}); the compression ratio of the engine is 10:1 (that is, the 1&nbsp;L volume of uncompressed gas is reduced to 0.1&nbsp;L by the piston); and the uncompressed gas is at approximately room temperature and pressure (a warm room temperature of ~27&nbsp;°C, or 300&nbsp;K, and a pressure of 1&nbsp;bar = 100&nbsp;kPa, i.e. typical sea-level atmospheric pressure).
The compression stroke in a [[gasoline engine]] can be used as an example of adiabatic compression. The model assumptions are: the uncompressed volume of the cylinder is {{nobr|one litre (1 L {{=}} 1000 cm{{sup|3}} {{=}} 0.001 m{{sup|3}} );}} the gas within is the air consisting of molecular nitrogen and oxygen only (thus a diatomic gas with 5 degrees of freedom, and so {{nobr|{{math| ''γ'' {{=}} {{sfrac|7|5}}}} );}} the compression ratio of the engine is 10:1 (that is, the 1&nbsp;L volume of uncompressed gas is reduced to 0.1&nbsp;L by the piston); and the uncompressed gas is at approximately room temperature and pressure (a warm room temperature of ~27&nbsp;°C, or 300&nbsp;K, and a pressure of 1&nbsp;bar = 100&nbsp;kPa, i.e. typical sea-level atmospheric pressure).


<math display="block">\begin{align}
<math display="block">\begin{align}
P_1 V_1^\gamma &= \mathrm{constant}_1 \\
P_1 V_1^\gamma &= \mathsf{constant}_1 \\
  & = 100\,000~\text{Pa} \times (0.001~\text{m}^3)^\frac75 \\
  & = 100\,000~\text{Pa} \times (0.001~\mathsf{m}^3)^\frac75 \\
  & = 10^5 \times 6.31 \times 10^{-5}~\text{Pa}\,\text{m}^{21/5} \\
  & = 10^5 \times 6.31 \times 10^{-5}~\mathsf{Pa}\,\mathsf{m}^{21/5} \\
  & = 6.31~\text{Pa}\,\text{m}^{21/5},
  & = 6.31~\text{Pa}\,\mathsf{m}^{21/5}\ ,
\end{align}</math>
\end{align}</math>


so the adiabatic constant for this example is about {{nowrap|6.31 Pa&thinsp;m<sup>4.2</sup>.}}
so the adiabatic constant for this example is about {{nobr|6.31 Pa·m{{sup|4.2}} .}}


The gas is now compressed to a 0.1&nbsp;L (0.0001&nbsp;m<sup>3</sup>) volume, which we assume happens quickly enough that no heat enters or leaves the gas through the walls. The adiabatic constant remains the same, but with the resulting pressure unknown
The gas is now compressed to a 0.1&nbsp;L (0.0001&nbsp;m<sup>3</sup>) volume, which we assume happens quickly enough that no heat enters or leaves the gas through the walls. The adiabatic constant remains the same, but with the resulting pressure unknown


<math display="block">\begin{align}  
<math display="block">\begin{align}  
P_2 V_2^\gamma &= \mathrm{constant}_1 \\
P_2 V_2^\gamma &= \mathsf{constant}_1 \\
&= 6.31~\text{Pa}\,\text{m}^{21/5} \\
&= 6.31~\mathsf{Pa}\,\mathsf{m}^{21/5} \\
&= P \times (0.0001~\text{m}^3)^\frac75,
&= P \times (0.0001~\mathsf{m}^3)^\frac75,
\end{align}</math>
\end{align}</math>


We can now solve for the final pressure<ref>{{cite book |last1=Atkins |first1=Peter |last2=de Paula |first2=Giulio |title=Atkins' Physical Chemistry |date=2006 |publisher=W. H. Freeman |isbn=0-7167-8759-8 |page=48 |edition=8th}}</ref>
We can now solve for the final pressure<ref>{{cite book |last1=Atkins |first1=Peter |last2=de Paula |first2=Giulio |title=Atkins' Physical Chemistry |year=2006 |publisher=W.H. Freeman |isbn=0-7167-8759-8 |page=48 |edition=8th }} </ref>


<math display="block">\begin{align}
<math display="block">\begin{align}
P_2 &= P_1\left (\frac{V_1}{V_2}\right)^\gamma \\
P_2 &= P_1 \left( \frac{V_1}{V_2} \right)^\gamma \\
&= 100\,000~\text{Pa} \times \text{10}^{7/5} \\
&= 100\ 000~\mathsf{Pa} \times {10}^{7/5} \\
&= 2.51 \times 10^6~\text{Pa}
&= 2.51 \times 10^6~\mathsf{Pa} \ ,
\end{align}</math>
\end{align}</math>


or 25.1&nbsp;bar. This pressure increase is more than a simple 10:1 compression ratio would indicate; this is because the gas is not only compressed, but the work done to compress the gas also increases its internal energy, which manifests itself by a rise in the gas temperature and an additional rise in pressure above what would result from a simplistic calculation of 10 times the original pressure.
or 25.1&nbsp;bar. This pressure increase is more than a simple 10:1 compression ratio would indicate; this is because the gas is not only compressed, but the work done to compress the gas also increases its internal energy, which manifests itself by a rise in the gas temperature and an additional rise in pressure above what would result from a simplistic calculation of 10 times the original pressure.


We can solve for the temperature of the compressed gas in the engine cylinder as well, using the ideal gas law, ''PV''&nbsp;=&nbsp;''nRT'' (''n'' is amount of gas in moles and ''R'' the gas constant for that gas). Our initial conditions being 100&nbsp;kPa of pressure, 1&nbsp;L volume, and 300&nbsp;K of temperature, our experimental constant (''nR'') is:
We can solve for the temperature of the compressed gas in the engine cylinder as well, using the ideal gas law, {{mvar|P V {{=}} n R T }} ({{mvar|n}} is amount of gas in moles and {{mvar|R}} the gas constant for that gas). Our initial conditions being 100&nbsp;kPa of pressure, 1&nbsp;L volume, and 300&nbsp;K of temperature, our experimental constant ({{mvar|n R}}{{hairsp}}) is:


<math display="block">\begin{align}
<math display="block">\begin{align}
\frac{PV}{T} &= \mathrm{constant}_2 \\
\frac{P\ V}{T} &= \mathsf{constant}_2 \\
&= \frac{10^5~\text{Pa} \times 10^{-3}~\text{m}^3}{300~\text{K}} \\
&= \frac{10^5~\mathsf{Pa} \times 10^{-3}~\mathsf{m}^3}{300~\mathsf{K}} \\
&= 0.333~\text{Pa}\,\text{m}^3\text{K}^{-1}.
&= 0.333~\mathsf{Pa}\ \mathsf{m}^3\mathsf{K}^{-1} ~.
\end{align}</math>
\end{align}</math>


We know the compressed gas has {{mvar|V}}&nbsp;= 0.1&nbsp;L and {{mvar|P}}&nbsp;= {{val|2.51|e=6|u=Pa}}, so we can solve for temperature:
We know the compressed gas has {{nobr|{{mvar|V}} {{=}} 0.1 L}} and {{nobr|{{mvar|P}} {{=}} {{val|2.51|e=6|u=Pa}},}} so we can solve for temperature:


<math display="block">\begin{align}
<math display="block">\begin{align}
T &= \frac{P V}{\mathrm{constant}_2} \\
T &= \frac{P\ V}{\mathsf{constant}_2} \\
&= \frac{2.51 \times 10^6~\text{Pa} \times 10^{-4}~\text{m}^3}{0.333~\text{Pa}\,\text{m}^3\text{K}^{-1}} \\
&= \frac{2.51 \times 10^6~\mathsf{Pa} \times 10^{-4}~\text{m}^3}{0.333~\mathsf{Pa}\ \mathsf{m}^3\mathsf{K}^{-1}} \\
&= 753~\text{K}.
&= 753~\mathsf{K}.
\end{align}</math>
\end{align}</math>


Line 129: Line 131:


===Derivation of ''P''–''V'' relation for adiabatic compression and expansion===
===Derivation of ''P''–''V'' relation for adiabatic compression and expansion===
The definition of an adiabatic process is that heat transfer to the system is zero, {{math|1=''δQ'' = 0}}. Then, according to the first law of thermodynamics,
The definition of an adiabatic process is that heat transfer to the system is zero, {{nobr|{{math|''δQ'' {{=}} 0}}.}} Then, according to the first law of thermodynamics,


{{NumBlk||<math display="block"> d U + \delta W = \delta Q = 0, </math>|{{EquationRef|a1}}}}
{{NumBlk||<math display="block"> \mathrm{d}U + \delta W = \delta Q = 0\ , </math>|{{EquationRef|a1}}}}


where {{math|''dU''}} is the change in the internal energy of the system and {{math|''δW''}} is work done ''by'' the system. Any work ({{math|''δW''}}) done must be done at the expense of internal energy {{math|''U''}}, since no heat {{math|''δQ''}} is being supplied from the surroundings. Pressure–volume work {{math|''δW''}} done ''by'' the system is defined as
where {{math|d''U''}} is the change in the internal energy of the system and {{math|''δW''}} is work done ''by'' the system. Any work {{nobr|({{math|''δW''}})}} done must be done at the expense of internal energy {{nobr|{{mvar|U}},}} since no heat {{mvar|δQ}} is being supplied from the surroundings. Pressure–volume work {{mvar|δW}} done ''by'' the system is defined as


{{NumBlk||<math display="block"> \delta W = P \, dV. </math>|{{EquationRef|a2}}}}
{{NumBlk||<math display="block"> \delta W = P \ \mathrm{d}V ~.</math>|{{EquationRef|a2}}}}


However, {{math|''P''}} does not remain constant during an adiabatic process but instead changes along with {{math|''V''}}.
However, {{mvar|P}} does not remain constant during an adiabatic process but instead changes along with {{mvar|V}}.


It is desired to know how the values of {{math|''dP''}} and {{math|''dV''}} relate to each other as the adiabatic process proceeds. For an ideal gas (recall ideal gas law {{math|1=''PV'' = ''nRT''}}) the internal energy is given by
It is desired to know how the values of {{math|d''P''}} and {{math|d''V''}} relate to each other as the adiabatic process proceeds. For an ideal gas (recall ideal gas law {{nobr|{{math|''PV'' {{=}} ''nRT''}})}} the internal energy is given by


{{NumBlk||<math display="block"> U = \alpha n R T = \alpha P V, </math>|{{EquationRef|a3}}}}
{{NumBlk||<math display="block"> U = \alpha\ n\ R\ T = \alpha\ P\ V\ , </math>|{{EquationRef|a3}}}}


where {{math|''α''}} is the number of degrees of freedom divided by 2, {{math|''R''}} is the [[universal gas constant]] and {{math|''n''}} is the number of moles in the system (a constant).
where {{mvar|α}} is the number of degrees of freedom divided by 2, {{mvar|R}} is the [[universal gas constant]] and {{mvar|n}} is the number of moles in the system (a constant).


Differentiating equation (a3) yields
Differentiating equation (a3) yields


{{NumBlk||<math display="block">\begin{align}
{{NumBlk||<math display="block">\begin{align}
d U &= \alpha n R \, dT\\
\mathrm{d} U &= \alpha\ n\ R\ \mathrm{d}T\\
                 & = \alpha \, d (P V)\\
                 & = \alpha\ \mathrm{d} (P\ V)\\
                 & = \alpha (P \, dV + V \, dP).
                 & = \alpha\ (P \ \mathrm{d}V + V \ \mathrm{d}P) ~.
\end{align}</math>|{{EquationRef|a4}}}}
\end{align}</math>|{{EquationRef|a4}}}}


Equation (a4) is often expressed as {{math|1=''dU'' = ''nC<sub>V</sub> dT''}} because {{math|1=''C<sub>V</sub>'' = ''αR''}}.
Equation (a4) is often expressed as {{math|d''U'' {{=}} ''n C<sub>V</sub> ''d''T''}} because {{nobr|{{math|''C<sub>V</sub>'' {{=}} ''α R''}} .}}


Now substitute equations (a2) and (a4) into equation (a1) to obtain
Now substitute equations (a2) and (a4) into equation (a1) to obtain


<math display="block"> -P \, dV = \alpha P \, dV + \alpha V \, dP,</math>
<math display="block"> -P\ \mathrm{d}V = \alpha\ P\ \mathrm{d}V + \alpha\ V\ \mathrm{d}P\ ,</math>


factorize {{math|−''P'' ''dV''}}:
factor {{math|−''P'' d''V''}}:


<math display="block"> -(\alpha + 1) P \, dV = \alpha V \, dP,</math>
<math display="block"> -(\alpha + 1)\ P\ \mathrm{d}V = \alpha V\ \mathrm{d}P\ ,</math>


and divide both sides by {{math|''PV''}}:
and divide both sides by {{mvar|P V }}:


<math display="block"> -(\alpha + 1) \frac{dV}{V} = \alpha \frac{dP}{P}. </math>
<math display="block"> -(\alpha + 1)\ \frac{\mathrm{d}V}{V} = \alpha\ \frac{\mathrm{d}P}{P} ~.</math>


After integrating the left and right sides from {{math|''V''<sub>0</sub>}} to {{math|''V''}} and from {{math|''P''<sub>0</sub>}} to {{math|''P''}} and changing the sides respectively,
After integrating the left and right sides from {{math|''V''<sub>0</sub>}} to {{mvar|V}} and from {{math|''P''<sub>0</sub>}} to {{mvar|P}} and changing the sides respectively,


<math display="block"> \ln \left( \frac{P}{P_0} \right) = -\frac{\alpha + 1}{\alpha} \ln \left( \frac{V}{V_0} \right). </math>
<math display="block"> \ln \left( \frac{P}{P_0} \right) = -\frac{\alpha + 1}{\alpha}\ \ln \left( \frac{V}{V_0} \right) ~.</math>


Exponentiate both sides, substitute {{math|{{sfrac|''α'' + 1|''α''}}}} with {{math|''γ''}}, the heat capacity ratio
Exponentiate both sides, substitute {{math|{{sfrac|''α'' + 1|''α''}}}} with {{mvar|γ}}, the heat capacity ratio


<math display="block"> \left( \frac{P}{P_0} \right) = \left( \frac{V}{V_0} \right)^{-\gamma}, </math>
<math display="block"> \left( \frac{P}{P_0} \right) = \left( \frac{V}{V_0} \right)^{-\gamma}\ ,</math>


and eliminate the negative sign to obtain
and eliminate the negative sign to obtain


<math display="block"> \left( \frac{P}{P_0} \right) = \left( \frac{V_0}{V} \right)^\gamma. </math>
<math display="block"> \left( \frac{P}{P_0} \right) = \left( \frac{V_0}{V} \right)^\gamma ~.</math>


Therefore,
Therefore,


<math display="block"> \left( \frac{P}{P_0} \right) \left( \frac{V}{V_0} \right)^\gamma = 1,</math>
<math display="block"> \left( \frac{P}{P_0} \right) \left( \frac{V}{V_0} \right)^\gamma = 1\ ,</math>


and
and


<math display="block"> P_0 V_0^\gamma = P V^\gamma = \mathrm{constant}. </math>
<math display="block"> P_0\ V_0^\gamma = P\ V^\gamma = \mathsf{constant} ~.</math>


{{NumBlk||<math display="block"> \Delta U = \alpha R nT_2 - \alpha R nT_1 = \alpha Rn \Delta T. </math>|{{EquationRef|b1}}}}
{{NumBlk||<math display="block"> \Delta U = \alpha\ R\ n\ T_2 - \alpha\ R\ n\ T_1 = \alpha\ R\ n\ \Delta T ~.</math>|{{EquationRef|b1}}}}


At the same time, the work done by the pressure–volume changes as a result from this process, is equal to
At the same time, the work done by the pressure–volume changes as a result from this process, is equal to


{{NumBlk||<math display="block"> W = \int_{V_1}^{V_2}P \,dV. </math>|{{EquationRef|b2}}}}
{{NumBlk||<math display="block"> W = \int_{V_1}^{V_2}\ P\ \mathrm{d}V ~.</math>|{{EquationRef|b2}}}}


Since we require the process to be adiabatic, the following equation needs to be true
Since we require the process to be adiabatic, the following equation needs to be true


{{NumBlk||<math display="block"> \Delta U + W = 0. </math>|{{EquationRef|b3}}}}
{{NumBlk||<math display="block"> \Delta U + W = 0 ~.</math>|{{EquationRef|b3}}}}


By the previous derivation,
By the previous derivation,


{{NumBlk||<math display="block"> P V^\gamma = \text{constant} = P_1 V_1^\gamma. </math>|{{EquationRef|b4}}}}
{{NumBlk||<math display="block"> P\ V^\gamma = \mathsf{constant} = P_1\ V_1^\gamma ~.</math>|{{EquationRef|b4}}}}


Rearranging (b4) gives
Rearranging (b4) gives


<math display="block"> P = P_1 \left(\frac{V_1}{V} \right)^\gamma. </math>
<math display="block"> P = P_1\ \left(\frac{V_1}{V} \right)^\gamma ~.</math>


Substituting this into (b2) gives
Substituting this into (b2) gives


<math display="block"> W = \int_{V_1}^{V_2} P_1 \left(\frac{V_1}{V} \right)^\gamma \,dV. </math>
<math display="block"> W = \int_{V_1}^{V_2} P_1\ \left(\frac{V_1}{V} \right)^\gamma\ \mathrm{d}V ~.</math>


Integrating, we obtain the expression for work,
Integrating, we obtain the expression for work,


<math display="block">\begin{align}
<math display="block">
W = P_1 V_1^\gamma \frac{V_2^{1-\gamma} - V_1^{1-\gamma}}{1 - \gamma} \\
\begin{align}
&= \frac{P_2 V_2 - P_1 V_1}{1 - \gamma}.
W &= P_1\ V_1^\gamma\ \frac{V_2^{1-\gamma} - V_1^{1-\gamma}}{1 - \gamma} \\[1ex]
\end{align}</math>
&= \frac{P_2\ V_2 - P_1\ V_1}{1 - \gamma}.
\end{align}
</math>


Substituting {{math|1=''γ'' = {{sfrac|''α'' + 1|''α''}}}} in the second term,
Substituting {{math|''γ'' {{=}} {{sfrac|''α'' + 1|''α''}}}} in the second term,


<math display="block"> W = -\alpha P_1 V_1^\gamma \left( V_2^{1-\gamma} - V_1^{1-\gamma} \right). </math>
<math display="block"> W = -\alpha\ P_1\ V_1^\gamma\ \left( V_2^{1-\gamma} - V_1^{1-\gamma} \right) ~.</math>


Rearranging,
Rearranging,


<math display="block"> W = -\alpha P_1 V_1 \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right). </math>
<math display="block"> W = -\alpha\ P_1\ V_1\ \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right) ~.</math>


Using the ideal gas law and assuming a constant molar quantity (as often happens in practical cases),
Using the ideal gas law and assuming a constant molar quantity (as often happens in practical cases),


<math display="block"> W = -\alpha n R T_1 \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right). </math>
<math display="block"> W = -\alpha\ n\ R\ T_1 \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right) ~.</math>


By the continuous formula,
By the continuous formula,


<math display="block"> \frac{P_2}{P_1} = \left(\frac{V_2}{V_1}\right)^{-\gamma}, </math>
<math display="block"> \frac{P_2}{P_1} = \left(\frac{V_2}{V_1}\right)^{-\gamma}\ ,</math>


or
or


<math display="block"> \left(\frac{P_2}{P_1}\right)^{-\frac{1}{\gamma}} = \frac{V_2}{V_1}. </math>
<math display="block"> \left(\frac{P_2}{P_1}\right)^{-\frac{1}{\gamma}} = \frac{V_2}{V_1} ~.</math>


Substituting into the previous expression for {{math|''W''}},
Substituting into the previous expression for {{mvar|W}},


<math display="block"> W = -\alpha n R T_1 \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right). </math>
<math display="block"> W = -\alpha\ n\ R\ T_1 \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right) ~.</math>


Substituting this expression and (b1) in (b3) gives
Substituting this expression and (b1) in (b3) gives


<math display="block"> \alpha n R (T_2 - T_1) = \alpha n R T_1 \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right). </math>
<math display="block"> \alpha\ n\ R\ (T_2 - T_1) = \alpha\ n\ R\ T_1\ \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right) ~.</math>


Simplifying,
Simplifying,


<math display="block">\begin{align}
<math display="block">\begin{align}
T_2 - T_1 &=  T_1 \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right), \\
T_2 - T_1 &=  T_1\ \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right)\ , \\
\frac{T_2}{T_1} - 1 &=  \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1, \\
\frac{T_2}{T_1} - 1 &=  \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1\ , \\
T_2 &= T_1 \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}}.
T_2 &= T_1\ \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} ~.
\end{align}</math>
\end{align}</math>


Line 257: Line 261:
<!-- equation missing here? TODO: check revisions -->At the same time, the work done by the pressure–volume changes as a result from this process, is equal to
<!-- equation missing here? TODO: check revisions -->At the same time, the work done by the pressure–volume changes as a result from this process, is equal to


{{NumBlk||<math display="block"> W = \int_{V_1}^{V_2}P \,dV. </math>|{{EquationRef|c2}}}}
{{NumBlk||<math display="block"> W = \int_{V_1}^{V_2}\ P\ \mathrm{d}V ~.</math>|{{EquationRef|c2}}}}


Since we require the process to be adiabatic, the following equation needs to be true
Since we require the process to be adiabatic, the following equation needs to be true


{{NumBlk||<math display="block"> \Delta U + W = 0. </math>|{{EquationRef|c3}}}}
{{NumBlk||<math display="block"> \Delta U + W = 0 ~.</math>|{{EquationRef|c3}}}}


By the previous derivation,
By the previous derivation,


{{NumBlk||<math display="block"> P V^\gamma = \text{constant} = P_1 V_1^\gamma. </math>|{{EquationRef|c4}}}}
{{NumBlk||<math display="block"> P\ V^\gamma = \text{constant} = P_1\ V_1^\gamma ~.</math>|{{EquationRef|c4}}}}


Rearranging (c4) gives
Rearranging (c4) gives


<math display="block"> P = P_1 \left(\frac{V_1}{V} \right)^\gamma. </math>
<math display="block"> P = P_1\ \left(\frac{V_1}{V} \right)^\gamma ~.</math>


Substituting this into (c2) gives
Substituting this into (c2) gives


<math display="block"> W = \int_{V_1}^{V_2} P_1 \left(\frac{V_1}{V} \right)^\gamma \,dV. </math>
<math display="block"> W = \int_{V_1}^{V_2} P_1\ \left(\frac{V_1}{V} \right)^\gamma\ \mathrm{d}V ~.</math>


Integrating we obtain the expression for work,
Integrating we obtain the expression for work,


<math display="block"> W = P_1 V_1^\gamma \frac{V_2^{1-\gamma} - V_1^{1-\gamma}}{1 - \gamma} = \frac{P_2 V_2 - P_1 V_1}{1 - \gamma}. </math>
<math display="block"> W = P_1\ V_1^\gamma \frac{V_2^{1-\gamma} - V_1^{1-\gamma}}{1 - \gamma} = \frac{P_2\ V_2 - P_1\ V_1}{1 - \gamma} ~.</math>


Substituting {{math|1=''γ'' = {{sfrac|''α'' + 1|''α''}}}} in second term,
Substituting {{math|1=''γ'' = {{sfrac|''α'' + 1|''α''}}}} in second term,


<math display="block"> W = -\alpha P_1 V_1^\gamma \left( V_2^{1-\gamma} - V_1^{1-\gamma} \right). </math>
<math display="block"> W = -\alpha\ P_1 V_1^\gamma\ \left( V_2^{1-\gamma} - V_1^{1-\gamma} \right) ~.</math>


Rearranging,
Rearranging,


<math display="block"> W = -\alpha P_1 V_1 \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right). </math>
<math display="block"> W = -\alpha\ P_1\ V_1\ \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right) ~.</math>


Using the ideal gas law and assuming a constant molar quantity (as often happens in practical cases),
Using the ideal gas law and assuming a constant molar quantity (as often happens in practical cases),


<math display="block"> W = -\alpha n R T_1 \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right). </math>
<math display="block"> W = -\alpha\ n\ R\ T_1\ \left( \left( \frac{V_2}{V_1} \right)^{1-\gamma} - 1 \right) ~.</math>


By the continuous formula,
By the continuous formula,


<math display="block"> \frac{P_2}{P_1} = \left(\frac{V_2}{V_1}\right)^{-\gamma}, </math>
<math display="block"> \frac{P_2}{P_1} = \left(\frac{V_2}{V_1}\right)^{-\gamma}\ ,</math>


or
or


<math display="block"> \left(\frac{P_2}{P_1}\right)^{-\frac{1}{\gamma}} = \frac{V_2}{V_1}. </math>
<math display="block"> \left(\frac{P_2}{P_1}\right)^{-\frac{1}{\gamma}} = \frac{V_2}{V_1} ~.</math>


Substituting into the previous expression for {{math|''W''}},
Substituting into the previous expression for {{math|''W''}},


<math display="block"> W = -\alpha n R T_1 \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right). </math>
<math display="block"> W = -\alpha\ n\ R\ T_1\ \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right) ~.</math>


Substituting this expression and (c1) in (c3) gives
Substituting this expression and (c1) in (c3) gives


<math display="block"> \alpha n R (T_2 - T_1) = \alpha n R T_1 \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right). </math>
<math display="block"> \alpha\ n\ R\ (T_2 - T_1) = \alpha\ n\ R\ T_1\ \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right) ~.</math>


Simplifying,
Simplifying,


<math display="block">\begin{align}
<math display="block">\begin{align}
T_2 - T_1 &=  T_1 \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right), \\
T_2 - T_1 &=  T_1\ \left( \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1 \right)\ , \\
\frac{T_2}{T_1} - 1 &=  \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1, \\
\frac{T_2}{T_1} - 1 &=  \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} - 1\ , \\
T_2 &= T_1 \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}}.
T_2 &= T_1\ \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}} ~.
\end{align}</math>
\end{align}</math>


Line 320: Line 324:
|The adiabats are isentropic.
|The adiabats are isentropic.
|Volume is the horizontal axis and pressure is the vertical axis.}}]]
|Volume is the horizontal axis and pressure is the vertical axis.}}]]
An adiabat is a curve of constant [[entropy]] in a diagram. Some properties of adiabats on a ''P''–''V'' diagram are indicated. These properties may be read from the classical behaviour of ideal gases, except in the region where ''PV'' becomes small (low temperature), where quantum effects become important.
An adiabat is a curve of constant [[entropy]] in a diagram. Some properties of adiabats on a {{math|''P'' – ''V''}} diagram are indicated. These properties may be read from the classical behaviour of ideal gases, except in the region where {{mvar|P V}} becomes small (low temperature), where quantum effects become important.


# Every adiabat [[asymptotically]] approaches both the ''V'' axis and the ''P'' axis (just like [[isotherms]]).
# Every adiabat [[asymptotically]] approaches both the {{mvar|V}}&nbsp;axis and the {{mvar|P}}&nbsp;axis (just like [[isotherms]]).
# Each adiabat intersects each isotherm exactly once.
# Each adiabat intersects each isotherm exactly once.
# An adiabat looks similar to an isotherm, except that during an expansion, an adiabat loses more pressure than an isotherm, so it has a steeper inclination (more vertical).
# An adiabat looks similar to an isotherm, except that during an expansion, an adiabat loses more pressure than an isotherm, so it has a steeper inclination (more vertical).
# If isotherms are concave towards the north-east direction (45° from V-axis), then adiabats are concave towards the east north-east (31° from V-axis).
# If isotherms are concave towards the north-east direction (45° from {{mvar|V}}&nbsp;axis), then adiabats are concave towards the east north-east (31° from {{mvar|V}}&nbsp;axisaxis).
# If adiabats and isotherms are graphed at regular intervals of entropy and temperature, respectively (like altitude on a contour map), then as the eye moves towards the axes (towards the south-west), it sees the density of isotherms stay constant, but it sees the density of adiabats grow. The exception is very near absolute zero, where the density of adiabats drops sharply and they become rare (see [[Nernst's theorem]]).{{clarify|reason=No quantitative formula is identified in that article as Nernst's theorem, only a qualitative "Impossibility Principle"|date=March 2015}}
# If adiabats and isotherms are graphed at regular intervals of entropy and temperature, respectively (like altitude on a contour map), then as the eye moves towards the axes (towards the south-west), it sees the density of isotherms stay constant, but it sees the density of adiabats grow. The exception is very near absolute zero, where the density of adiabats drops sharply and they become rare (see [[Nernst's theorem]]).{{clarify|reason=No quantitative formula is identified in that article as Nernst's theorem, only a qualitative "Impossibility Principle"|date=March 2015}}


==Etymology==
==Etymology==
The term ''adiabatic'' ({{IPAc-en|ˌ|æ|d|i|ə|ˈ|b|æ|t|ɪ|k}}) is an anglicization of the [[Ancient Greek|Greek]] term ἀδιάβατος "impassable" (used by [[Xenophon]] of rivers). It is used in the thermodynamic sense by [[William John Macquorn Rankine|Rankine]] (1866),<ref name="Rankine 1866">[[William John Macquorn Rankine|Rankine, William John MacQuorn]] (1866). On the theory of explosive gas engines, ''The Engineer'', July 27, 1866; at page 467 of the reprint in ''[[iarchive:miscellaneoussci00rank|Miscellaneous Scientific Papers]]'', edited by W. J. Millar, 1881, Charles Griffin, London.</ref><ref name= "Partington 122">{{Citation
The term ''adiabatic'' ({{IPAc-en|ˌ|æ|d|i|ə|ˈ|b|æ|t|ɪ|k}}) is an anglicization of the [[Ancient Greek|Greek]] term {{math|ἀδιάβατος}} "impassable" (used by [[Xenophon]] of rivers). It is used in the thermodynamic sense by [[William John Macquorn Rankine|Rankine]] (1866),<ref name="Rankine 1866">{{cite journal |author-link=William John Macquorn Rankine |last=Rankine |first=W.J.McQ. |date=27 July 1866 |title=On the theory of explosive gas engines |journal=The Engineer |page=467}} Page number from the reprint in {{cite book |author-link=William John Macquorn Rankine |last=Rankine |first=W.J.McQ. |year=1881 |title=[[iarchive:miscellaneoussci00rank|Miscellaneous Scientific Papers]] |editor-first=W.J. |editor-last=Millar |publisher=Charles Griffin |place=London, UK }} </ref><ref name= "Partington 122">{{Citation
| last = Partington
| last = Partington
| first = J. R.
| first = J.R.
| author-link = J.R. Partington
| author-link = J.R. Partington
| title = An Advanced Treatise on Physical Chemistry.
| title = An Advanced Treatise on Physical Chemistry.
Line 354: Line 358:
The etymological origin corresponds here to an impossibility of [[Heat|transfer of energy as heat]] and of transfer of matter across the wall.
The etymological origin corresponds here to an impossibility of [[Heat|transfer of energy as heat]] and of transfer of matter across the wall.


The Greek word ἀδιάβατος is formed from [[privative a|privative ἀ-]] ("not") and διαβατός, "passable", in turn deriving from διά ("through"), and βαῖνειν ("to walk, go, come").<ref>[[Henry Liddell|Liddell, H. G.]], [[Robert Scott (philologist)|Scott, R.]] (1940). ''A Greek-English Lexicon'', Clarendon Press, Oxford, UK.</ref>
The Greek word {{math|ἀδιάβατος}} is formed from [[privative a|privative {{math|ἀ-}}]] ("not") and {{math|διαβατός}}, "passable", in turn deriving from {{math|διά}} ("through"), and {{math|βαῖνειν}} ("to walk, go, come").<ref>{{cite book |author1-link=Henry Liddell |last1=Liddell |first1=H.G. |author2-link=Robert Scott (philologist) |last2=Scott |first2=R. |year=1940 |title=[[A Greek-English Lexicon]] |publisher=Clarendon Press |place=Oxford, UK }} </ref>


Furthermore, in [[atmospheric thermodynamics]], a diabatic process is one in which heat is exchanged.<ref>{{cite web|url=https://glossary.ametsoc.org/wiki/Diabatic_process|title=diabatic process|access-date=24 November 2020|publisher=American Meteorological Society}}</ref> An adiabatic process is the opposite – a process in which no heat is exchanged.
Furthermore, in [[atmospheric thermodynamics]], a diabatic process is one in which heat is exchanged.<ref>{{cite web |title=diabatic process |publisher=[[American Meteorological Society]] |url=https://glossary.ametsoc.org/wiki/Diabatic_process |access-date=24 November 2020 }}</ref> An adiabatic process is the opposite – a process in which no heat is exchanged.


==Conceptual significance in thermodynamic theory==
==Conceptual significance in thermodynamic theory==
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{{quote|Actually, it is usually the 'adiabatic' case with which we have to do: i.e. the limiting case where the external force (or the reaction of the parts of the system on each other) acts very slowly. In this case, to a very high approximation
{{quote|Actually, it is usually the 'adiabatic' case with which we have to do: i.e. the limiting case where the external force (or the reaction of the parts of the system on each other) acts very slowly. In this case, to a very high approximation


<math display="block">c_1^2=1,\,\,c_2^2=0,\,\,c_3^2=0,\,...\,,</math>
<math display="block">c_1^2 = 1, ~ c_2^2=0, ~ c_3^2=0,\ ... ~.</math>


that is, there is no probability for a transition, and the system is in the initial state after cessation of the perturbation. Such a slow perturbation is therefore reversible, as it is classically.<ref>{{cite journal|last=Born |first=M. |author-link=Max Born |date=1927 |title=Physical aspects of quantum mechanics |journal=Nature |volume=119 |issue=2992 |pages=354–357|bibcode = 1927Natur.119..354B |doi = 10.1038/119354a0 |doi-access=free |translator-first=Robert |translator-last=Oppenheimer |translator-link=Robert Oppenheimer}}</ref>}}
that is, there is no probability for a transition, and the system is in the initial state after cessation of the perturbation. Such a slow perturbation is therefore reversible, as it is classically.<ref>{{cite journal|last=Born |first=M. |author-link=Max Born |date=1927 |title=Physical aspects of quantum mechanics |journal=Nature |volume=119 |issue=2992 |pages=354–357|bibcode = 1927Natur.119..354B |doi = 10.1038/119354a0 |doi-access=free |translator-first=Robert |translator-last=Oppenheimer |translator-link=Robert Oppenheimer}}</ref>}}
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==See also==
==See also==
{|
|-
|style="vertical-align:top;"|
; General
* [[Fire piston]]
* [[Fire piston]]
* [[Heat burst]]
* [[Heat burst]]
|style="vertical-align:top;"|
; Related physics topics
; Related physics topics
{{div col begin|colwidth=15em}}
* [[First law of thermodynamics]]
* [[First law of thermodynamics]]
* [[Entropy (classical thermodynamics)]]
* [[Entropy (classical thermodynamics)]]
Line 402: Line 412:
* [[Magnetic refrigeration]]
* [[Magnetic refrigeration]]
* [[Berry phase]]
* [[Berry phase]]
{{div col end}}
|style="vertical-align:top;"|
{{div col begin|colwidth=20em}}
; Related thermodynamic processes
; Related thermodynamic processes
* [[Cyclic process]]
* [[Cyclic process]]
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* [[Polytropic process]]
* [[Polytropic process]]
* [[Quasistatic process]]
* [[Quasistatic process]]
{{div col end}}
|}


==References==
==References==
{{Reflist|30em}}
{{reflist|25em}}


;General
;General
{{refbegin|25em|small=y}}
*{{cite web |title=Lecture 5: Definition of Heat Interaction |website=MIT OpenCourseWare |series=2.43 Advanced Thermodynamics |publisher=MIT |date=Spring 2024 |url=https://www.youtube.com/watch?v=Vn--WpmhFS4 }}
* {{cite book |first=Robert J. |last=Silbey |year=2004 |title=Physical chemistry |location=Hoboken, New Jersey |publisher=Wiley |page=55 |language=en-us |isbn=978-0-471-21504-2 |display-authors=etal}}
* {{cite book |first=Robert J. |last=Silbey |year=2004 |title=Physical chemistry |location=Hoboken, New Jersey |publisher=Wiley |page=55 |language=en-us |isbn=978-0-471-21504-2 |display-authors=etal}}
* Nave, Carl Rod. "[http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/adiab.html Adiabatic Processes]". HyperPhysics.
* Nave, Carl Rod. "[http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/adiab.html Adiabatic Processes]". HyperPhysics.
* Thorngren, Dr. Jane R. "[http://daphne.palomar.edu/jthorngren/adiabatic_processes.htm Adiabatic Processes]". Daphne – A Palomar College Web Server, 21 July 1995. {{Webarchive|url=https://web.archive.org/web/20110509121743/http://daphne.palomar.edu/jthorngren/adiabatic_processes.htm |date=2011-05-09 }}.
* Thorngren, Dr. Jane R. "[http://daphne.palomar.edu/jthorngren/adiabatic_processes.htm Adiabatic Processes]". Daphne – A Palomar College Web Server, 21 July 1995. {{Webarchive|url=https://web.archive.org/web/20110509121743/http://daphne.palomar.edu/jthorngren/adiabatic_processes.htm |date=2011-05-09 }}
{{refend}}


==External links==
== External links ==
{{Wiktionary|adiabatic}}
{{Wiktionary|adiabatic}}
{{Commons category-inline}}
{{Commons category-inline}}
*[http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/adiab.html#c1: Article in HyperPhysics Encyclopaedia]
* [http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/adiab.html#c1: Article in HyperPhysics Encyclopaedia]


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{{DEFAULTSORT:Adiabatic Process}}
{{DEFAULTSORT:Adiabatic Process}}